Question

2log3 27-log1/5 125-lg1000

Answer 1

Ответ:

$6$

Пошаговое объяснение:

$2log_327-log_{\frac{1}{5}}125-lg1000=2log_33^3-(-log_55^3)-lg10^3=\\\\=2*3log_33+3log_55-3lg10=6+3-3=6$

Answer 2

Ответ:

6

Пошаговое объяснение:

2log3 27-log1/5 125-lg 1000=2*3+3-3=6

Answer 3

Let's simplify the expression using the properties of logarithms:

2log3 27 - log1/5 125 - lg1000 = 2 * log3 (3^3) - log(1/5) (5^3) - log10 (10^3) [using the exponent rule of logarithms] = 2 * 3 - (-3) - 3 [using the logarithmic identities loga (a) = 1 and loga (1/x) = -loga (x)] = 6 + 3 - 3 = 6

Therefore, 2log3 27 - log1/5 125 - lg1000 = 6.