Question

Решить задачу.расстояние между городами А и В 360 км.из А и В выехал автобус со скоростью 50 км\ч.через 3 часа навстречу ему из В и А выехал мотоциклист со скоростью 55км\ч.через сколько часов после выезда автобуса они встретиться?

Answer 1

50 х 3 =150км проехал автобус за 3 ч
360 -150 = 210 км между автобусом и мото
55+50 =105 км/ч общая скорость или скорость сближения
210 : 105 =через 2 часа встретятся

Answer 2

Problem Analysis

We are given that the distance between cities A and B is 360 km. An bus leaves from city A towards city B with a speed of 50 km/h. After 3 hours, a motorcyclist leaves from city B towards city A with a speed of 55 km/h. We need to find out how many hours after the bus's departure they will meet.

Solution

Let's assume that they meet after t hours.

During the first 3 hours, the bus covers a distance of 3 * 50 = 150 km. So, the remaining distance between the bus and the motorcyclist is 360 - 150 = 210 km.

Now, both the bus and the motorcyclist are moving towards each other. The combined speed of the bus and the motorcyclist is 50 + 55 = 105 km/h.

Using the formula `distance = speed * time`, we can calculate the time it takes for them to meet:

210 km = 105 km/h * t

Simplifying the equation, we get:

t = 210 km / 105 km/h = 2 hours

Therefore, they will meet 2 hours after the bus's departure.

Answer

They will meet 2 hours after the bus's departure.