Question

1) 3/10х = 2 целых 1/42) 2/20х = 1 целая 4/53) 28/32х = 2 целях 1/64) 11/16х = 3/4

Answer 1

1.)семь целых 5/10
2.)восемнадцать
3.)две целых 10/21
4.)одна целая 1/11

Answer 2

To solve these equations, we can use the concept of cross-multiplication. Let's solve each equation step by step:

1. 3/10x = 2 + 1/4

To eliminate the fractions, we can multiply both sides of the equation by the least common multiple (LCM) of the denominators. The LCM of 10 and 4 is 20.

20 * (3/10x) = 20 * (2 + 1/4)

6x = 40 + 5

6x = 45

Now, we can solve for x:

x = 45/6

Simplifying the fraction:

x = 7 1/2

2. 2/20x = 1 + 4/5

Multiplying both sides by the LCM of 20 and 5, which is 20:

20 * (2/20x) = 20 * (1 + 4/5)

x = 20 + 16

x = 36

3. 28/32x = 2 + 1/64

Multiplying both sides by the LCM of 32 and 64, which is 64:

64 * (28/32x) = 64 * (2 + 1/64)

56x = 128 + 1

56x = 129

x = 129/56

4. 11/16x = 3/4

Multiplying both sides by the LCM of 16 and 4, which is 16:

16 * (11/16x) = 16 * (3/4)

11x = 12

x = 12/11