Question

Ребят,помогите пожалуйста,геометрия, 7 класс На рисунке 35 отрезки AB и CD имеют общую середину О. Докажите, что ∠ DAO=∠CBO. УМОЛЯЯЮЮЮЮЮ

Answer 1

Вроде бы правильно, принимайте ответ))

Answer 2

Proof that ∠DAO = ∠CBO

To prove that ∠DAO = ∠CBO, we can use the fact that the segments AB and CD have a common midpoint O.

Let's consider the triangles ADO and BCO.

Since O is the midpoint of AB, we know that AO = BO and DO = CO.

By the Side-Angle-Side (SAS) congruence criterion, if we can show that AO = BO and ∠ADO = ∠BCO, then we can conclude that the triangles ADO and BCO are congruent.

To prove that ∠ADO = ∠BCO, we can use the fact that corresponding angles of congruent triangles are equal.

Therefore, if we can show that the triangles ADO and BCO are congruent, we can conclude that ∠DAO = ∠CBO.

Let's proceed with the proof.

Proof:

1. Given: AB and CD have a common midpoint O. 2. To prove: ∠DAO = ∠CBO.

Proof:

Step 1: Since O is the midpoint of AB, we have AO = BO. (Given)

Step 2: Since O is the midpoint of CD, we have DO = CO. (Given)

Step 3: Draw segment AD and segment BC.

Step 4: Consider triangles ADO and BCO.

Step 5: By the Side-Angle-Side (SAS) congruence criterion, if we can show that AO = BO and ∠ADO = ∠BCO, then we can conclude that the triangles ADO and BCO are congruent.

Step 6: From Step 1, we have AO = BO.

Step 7