Вопрос задан 17.02.2019 в 14:08. Предмет Геометрия. Спрашивает Тагирова Амира.

Ко-перпендикуляр к плоскости, КМ и КР-НАКЛОННЫЕ к плоскости, ОМ и ОР-их проекции, причём

ом=1/3ОР.Найдите расстояние от точки К до плоскости, если КМ =6, КР =10 Подробно и с рисунком пожалуйста
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Отвечает Царев Женя.
Решение во вложенном файле.
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Finding the Distance from Point K to the Plane

To find the distance from point K to the plane, we need to use the given information about the inclinations and projections of the lines KM and KR, as well as the relationship between OM and OR.

Let's break down the problem step by step:

1. Identify the given information: - KM = 6 - KR = 10 - OM = 1/3 * OR

2. Understand the problem: We have a plane and two lines, KM and KR, that are inclined to the plane. We also have the projections of these lines, OM and OR, respectively. We need to find the distance from point K to the plane.

3. Analyze the given information: - KM and KR are inclined to the plane. - OM and OR are the projections of KM and KR, respectively. - OM = 1/3 * OR

4. Visualize the problem: ![Visualization](https://example.com/visualization)

5. Solve the problem: To find the distance from point K to the plane, we can use the formula for the distance between a point and a plane. The formula is:

Distance = |ax + by + cz + d| / sqrt(a^2 + b^2 + c^2)

In this formula, (x, y, z) represents the coordinates of the point, and (a, b, c) represents the coefficients of the plane's equation. The constant d is the distance from the origin to the plane.

To use this formula, we need to find the equation of the plane. Since we don't have the equation explicitly given, we can use the normal vector of the plane to find the coefficients (a, b, c).

The normal vector of the plane is perpendicular to the plane. Since KM and KR are inclined to the plane, their projections OM and OR are perpendicular to the normal vector. Therefore, we can find the normal vector by taking the cross product of OM and OR.

Let's calculate the normal vector:

OM = 1/3 * OR OM = (1/3) * (ORx, ORy, ORz)

The cross product of OM and OR will give us the normal vector:

Normal vector = OM x OR Normal vector = (OMy * ORz - OMz * ORy, OMz * ORx - OMx * ORz, OMx * ORy - OMy * ORx)

Now that we have the normal vector, we can find the coefficients (a, b, c) of the plane's equation.

Once we have the equation of the plane, we can substitute the coordinates of point K into the distance formula to find the distance from K to the plane.

6. Provide the solution: Unfortunately, I couldn't find the specific equation for the plane or the normal vector using the given information. However, I can guide you through the steps to find the solution once you have the equation of the plane.

If you have any additional information or if there's anything else I can help you with, please let me know!

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