Question

Основание пирамиды-прямоугольник со сторонами 6см и 8см. Высота пирамиды проходит через точку пересечения диагоналей основания и равна 12 см. Найти площадь полной поверхности и объем пирамиды

Answer 1

очень все легко 

находим диагональ основания

х^2=6^2+8^2

x^2=36+64=100

x=10

 УДАЧИ)))

Answer 2

Given Information:

- The base of the pyramid is a rectangle with sides measuring 6 cm and 8 cm. - The height of the pyramid passes through the point of intersection of the diagonals of the base and is equal to 12 cm.

Finding the Surface Area of the Pyramid:

To find the surface area of the pyramid, we need to calculate the area of the base and the area of the four triangular faces.

1. Area of the Base: - The base of the pyramid is a rectangle with sides measuring 6 cm and 8 cm. - The area of a rectangle is given by the formula: Area = length × width. - Therefore, the area of the base is 6 cm × 8 cm = 48 cm².

2. Area of the Triangular Faces: - The four triangular faces of the pyramid are congruent. - To find the area of one triangular face, we need to calculate the length of the base of the triangle. - The base of the triangle is the length of the diagonal of the rectangle, which can be found using the Pythagorean theorem. - The Pythagorean theorem states that in a right