Question

ТРЕУГОЛЬНИКИ ABC И A1B1C1 РАВНОБЕДРЕННЫЕ С ОСНОВАНИЯМИ BC И B1C1 ,ПРИЧЕМ AB =A1B1 И BC=B1C1 . ДОКАЖИТЕ , ЧТО БИССЕКТРИСА СH РАВНА БИССЕКТРИСЕ C1 H1

Answer 1

Обожешь ты мой.. такую фигну половину людей позабыло.. хах

Answer 2

Problem Statement

We are given two isosceles triangles, ABC and A1B1C1, with bases BC and B1C1, respectively. It is also given that AB = A1B1 and BC = B1C1. We need to prove that the bisector CH is equal to the bisector C1H1.

Proof

To prove that the bisector CH is equal to the bisector C1H1, we can use the properties of isosceles triangles and the fact that the bases BC and B1C1 are equal.

Let's consider triangle ABC. Since AB = A1B1, we can conclude that triangle ABC is congruent to triangle A1B1C1 by the Side-Side-Side (SSS) congruence criterion.

Now, let's focus on triangle ABC. Since triangle ABC is isosceles with base BC, we know that the altitude from vertex A will bisect BC at point H. Similarly, in triangle A1B1C1, the altitude from vertex A1 will bisect B1C1 at point H1.

Since triangle ABC is congruent to triangle A1B1C1, the corresponding parts are congruent as well. Therefore, the bisector CH is equal to the bisector C1H1.

In conclusion, we have proved that the bisector CH is equal to the bisector C1H1 in triangles ABC and A1B1C1.

Note: The provided sources did not contain specific information related to the problem statement. However, the proof is based on the properties of isosceles triangles and the congruence of corresponding parts in congruent triangles.