Question

СРОЧНООООО!!!! ДАЮ 50 БАЛЛОВ !!!!!!! Дана окружность радиусом 12 см. Расстояние от центра окружности до хорды равно 6 см. Найдите угол между радиусами, проведенными к концам хорды.

Answer 1

Сам распишешь. Ответ будет такой

Answer 2

18смааааааапаппппппппапп

Answer 3

Problem Analysis

We are given a circle with a radius of 12 cm. The distance from the center of the circle to a chord is 6 cm. We need to find the angle between the radii drawn to the ends of the chord.

Solution

To find the angle between the radii, we can use the properties of a circle and the properties of triangles formed by the radii and the chord.

Let's consider the triangle formed by the center of the circle, one end of the chord, and the center of the circle. This triangle is an isosceles triangle because the radii are equal in length (both are equal to the radius of the circle, which is 12 cm). The base of this triangle is the chord, and we are given that the distance from the center of the circle to the chord is 6 cm.

Using the properties of isosceles triangles, we know that the angles opposite the equal sides are equal. Therefore, the angle between the radii drawn to the ends of the chord is equal to half of the angle at the center of the circle that subtends the chord.

To find this angle, we can use the formula for the angle subtended by a chord at the center of a circle. The formula is:

Angle at the center = 2 * arcsin(chord length / (2 * radius))

Substituting the given values, we have:

Angle at the center = 2 * arcsin(6 / (2 * 12))

Simplifying further:

Angle at the center = 2 * arcsin(1/4) = 2 * 14.4775 degrees = 28.955 degrees

Therefore, the angle between the radii drawn to the ends of the chord is approximately 28.955 degrees.

Answer

The angle between the radii drawn to the ends of the chord is approximately 28.955 degrees.