Question

Биссектриса угол С палеограма АВСD делит стороны АD на отрезки DM и MA так, что DM: MA = 5: 2.Знайты стороны паралеграм если Р АВСD = 48с Срочно помогите пожалуйста

Answer 1

Ответ:

AD = BC = 11 + 5 = 16 см

Средняя линия MK = (AD + NC)/2 = (16 + 5)/2 = 21/2 = 10,5 см

2) Угол NAB = NAD = a, BCD = BAD = 2a, ABC = ADC = 180 - 2a

У трапеции ANCD сумма углов 360

ANC = 360 - NAD - NCD - ADC = 360 - a - 2a - 180 + 2a = 180 - a

ANB = 180 - ANC = a = NAD.

Треугольник NAD - равнобедренный, у него два угла равны.

AB = CD = BN = 11 см

Периметр P(ABCD) = 2*11 + 2(11+5) = 22 + 32 = 54 см.

Answer 2

I will try to answer your question in detail. The bisector of angle C of the parallelogram ABCD divides the side AD into segments DM and MA such that DM:MA = 5:2. Find the sides of the parallelogram if P ABCD = 48 cm. Please help me urgently.

To solve this problem, we need to use the following properties of the bisector and the parallelogram:

- The bisector of an angle of a parallelogram divides the opposite side in the same ratio as the adjacent sides. - The perimeter of a parallelogram is equal to the sum of the lengths of two pairs of opposite sides.

Let x be the length of the side AB and y be the length of the side BC. Then, by the first property, we have:

$$\\frac{DM}{MA} = \\frac{BC}{AB}$$

$$\\frac{5}{2} = \\frac{y}{x}$$

$$5x = 2y$$

By the second property, we have:

$$P_{ABCD} = 2(AB + BC)$$

$$48 = 2(x + y)$$

$$24 = x + y$$

Solving the system of equations, we get:

$$x = \\frac{48}{13}$$

$$y = \\frac{120}{13}$$

Therefore, the sides of the parallelogram are 3.69 cm and 9.23 cm.