Question

В параллелограмме BCDE биссектриса угла В пересекает сторону DE в точке К так, что DK= 4, а KE= 12. Найдите P параллелограмма. РЕБЯТ СРОЧНО ОЧЕНЬ В ГЕОМЕТРИИ ВООБЩЕ НЕ РАЗБИРАЮСЬ ПРОШУ (ВСЁ ПОДРОБНО НАПИСАТЬ ПОЖАЛУЙСТАААА))))

Answer 1

Угол СВК=углу ВКЕ  (как накрест лежащий при параллельных прямых),
значит и угол КВЕ= углу ВКЕ,  тогда треугольник ВКЕ равнобедренный     
ВЕ=КЕ=12
Р=(12+(12+4))*2=56

Answer 2

В параллелограмме BCDE биссектриса угла В пересекает сторону DE в точке К так, что DK = 4, а KE = 12. Нам нужно найти периметр параллелограмма P.

Understanding the Problem

To find the perimeter of the parallelogram, we need to know the lengths of all four sides. We are given that DK = 4 and KE = 12, but we need to determine the lengths of the other sides.

Solving the Problem

Let's analyze the given information and use it to find the lengths of the other sides of the parallelogram.

Since DK = 4 and KE = 12, we can conclude that DE = DK + KE = 4 + 12 = 16.

In a parallelogram, opposite sides are equal in length. Therefore, BC = DE = 16.

Now, we can calculate the perimeter of the parallelogram P by adding up the lengths of all four sides:

P = BC + CD + DE + EB

Since BC = DE = 16, we can simplify the equation:

P = 16 + CD + 16 + EB

To find the lengths of CD and EB, we need to use the fact that the bisector of angle B intersects side DE at point K. This means that DK = KE.

Since DK = 4 and KE = 12, we can conclude that CD = DK = 4 and EB = KE = 12.

Now, we can substitute the values into the equation for the perimeter:

P = 16 + 4 + 16 + 12

Simplifying further:

P = 48

Therefore, the perimeter of the parallelogram is 48.

Conclusion

In the given parallelogram BCDE, where the bisector of angle B intersects side DE at point K with DK = 4 and KE = 12, the perimeter of the parallelogram P is 48.