Question

X+2y=4Xквадрат2 +xy=6

Answer 1

Ответ:

В объяснении.

Объяснение:

х+2у=4

(0;2)→0+2*2=0+4=4. Верно.

Answer 2

It looks like you've written a system of two equations with two variables:

1. x + 2y = 4
2. x^2 + xy = 6

To solve this system of equations, you can use various methods such as substitution or elimination. Let's use the substitution method:

From equation 1, we can express x in terms of y: x = 4 - 2y

Now, substitute this expression for x into equation 2:

(4 - 2y)^2 + (4 - 2y)y = 6

Expand and simplify:

(16 - 16y + 4y^2) + (4y - 2y^2) = 6

Combine like terms:

4y^2 - 16y + 16 - 2y^2 + 4y = 6

Now, simplify further:

2y^2 - 16y + 16 = 6

Subtract 6 from both sides:

2y^2 - 16y + 10 = 0

Divide the entire equation by 2 to simplify:

y^2 - 8y + 5 = 0

Now, we have a quadratic equation in terms of y. We can solve it using the quadratic formula:

y = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 1, b = -8, and c = 5. Plugging these values into the formula:

y = (8 ± √((-8)^2 - 4(1)(5))) / (2(1))

y = (8 ± √(64 - 20)) / 2

y = (8 ± √44) / 2

y = (8 ± 2√11) / 2

Now, simplify:

y = 4 ± √11

So, there are two possible values for y:

1. y = 4 + √11
2. y = 4 - √11

Now that we have the values of y, we can find the corresponding values of x using the expression we found for x earlier:

For y = 4 + √11: x = 4 - 2(4 + √11) x = 4 - 8 - 2√11 x = -4 - 2√11

For y = 4 - √11: x = 4 - 2(4 - √11) x = 4 - 8 + 2√11 x = -4 + 2√11

So, the solutions to the system of equations are:

1. x = -4 - 2√11, y = 4 + √11
2. x = -4 + 2√11, y = 4 - √11