Question

А=30 в=40 с=35 найти углы

Answer 1

Для решения задачи нужно использовать теорему косинусов:

cosα=(B²+C²-A²)/2BC=(40²+35²-30²)/2*40*35=1925/2800=0,6875

по таблице Брадиса получаем α=47°

cosβ=(А²+C²-В²)/2АC=(30²+35²-40²)/2*30*35=525/2100=0,25

β=75°

третий угол =180-α-β=180-47-75=58°

Ответ: 47°, 58°, 75°

Answer 2

To find the angles in a triangle when given the side lengths, we can use the Law of Cosines and the Law of Sines. However, there seems to be a mistake in the information provided. The side lengths A, B, and C should refer to the lengths of the sides of the triangle, not angles. Angles are typically denoted by uppercase letters, such as A, B, and C.

If you have the side lengths of a triangle, you can find the angles using the Law of Cosines and the Law of Sines. The Law of Cosines states:

$c^2 = a^2 + b^2 - 2ab\cos(C)$

where $a$, $b$, and $c$ are the side lengths of the triangle, and $C$ is the angle opposite side $c$.

The Law of Sines states:

$\frac{\sin(A)}{a} = \frac{\sin(B)}{b} = \frac{\sin(C)}{c}$

where $A$, $B$, and $C$ are the angles of the triangle, and $a$, $b$, and $c$ are the side lengths opposite those respective angles.

Since you've provided side lengths (A=30, B=40, C=35), we cannot directly find the angles without more information. Please provide the correct information, and I'll be happy to help you find the angles of the triangle.