Question

В равнобедренном треугольнике MKL с основанием ML и угол KLM = 77° проведена биссектриса КР так, что угол MKP = 13°, а МР 4 см 3 мм. Определи величину углов PKL и КМР , а также длину стороны ML. ​

Answer 1

Ответ:

Я хзлол

Объяснение:

Потому что

Answer 2

Problem Analysis

We are given a triangle MKL with base ML and angle KLM = 77°. A bisector KR is drawn such that angle MKP = 13° and MR = 4 cm 3 mm. We need to determine the angles PKL and KMR, as well as the length of side ML.

Solution

To solve this problem, we can use the properties of isosceles triangles and the angle bisector theorem.

Let's start by finding the length of side ML. Since triangle MKL is isosceles with base ML, we know that the lengths of sides MK and KL are equal. Let's denote this length as x.

According to the angle bisector theorem, the ratio of the lengths of the segments formed by the angle bisector is equal to the ratio of the lengths of the opposite sides. In this case, we have:

MR / RK = ML / KL

Substituting the given values, we have:

4 cm 3 mm / RK = x / x

Simplifying, we get:

4 cm 3 mm = RK

Now, let's find the angles PKL and KMR. Since MKP is an angle in triangle MKL, we can use the fact that the sum of the angles in a triangle is 180°:

MKP + PKL + KLM = 180°

Substituting the given values, we have:

13° + PKL + 77° = 180°

Simplifying, we get:

PKL = 90°

Similarly, since KMR is an angle in triangle MKR, we can use the fact that the sum of the angles in a triangle is 180°:

KMR + MKR + MKP = 180°

Substituting the given values, we have:

KMR + MKR + 13° = 180°

Simplifying, we get:

KMR + MKR = 167°

Now, let's summarize the results:

- Angle PKL = 90° - Angle KMR = 167° - Length of side ML = 4 cm 3 mm

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