Question

1. Дан треугольник АВС. Отрезок ВЕ –биссектриса угла В к стороне АС. Через точку Е проведена прямая пересекающая сторону ВС в точке Д так, что ВД=ЕД. Докажите, что прямые КД и АВ параллельны. Срочно!

Answer 1

1. Угол АВ равен 90.пусть х ВС, тогда АС равен 2х.сост. уравнение
х+2х=90
3х=90
х=30
Угол ВС=30
Угол АС=2х
Ас=2*30=60

Answer 2

Given Information

We are given a triangle ABC, where BE is the angle bisector of angle B towards side AC. A line is drawn through point E, intersecting side BC at point D, such that BD = ED. We need to prove that lines KD and AB are parallel.

Proof

To prove that lines KD and AB are parallel, we can use the angle bisector theorem and the fact that BD = ED.

1. By the angle bisector theorem, we know that the ratio of the lengths of the segments formed by the angle bisector is equal to the ratio of the lengths of the opposite sides. In this case, we have: - BD/DC = BE/EC

2. Since BD = ED, we can substitute BD for ED in the equation above: - ED/DC = BE/EC

3. We can rewrite the equation as follows: - ED/DC = BE/EC = BD/DC

4. By the transitive property of equality, we can conclude that ED/DC = BD/DC.

5. Since the lengths of the segments formed by the angle bisector are equal, we can conclude that the angles formed by these segments are also equal. Therefore, angle EDC = angle BDC.

6. Since angle EDC = angle BDC, and angle BDC is an exterior angle of triangle ABC, we can conclude that angle BDC = angle ABC.

7. By the alternate interior angles theorem, we can conclude that angle ABC = angle KDC.

8. Since angle ABC = angle KDC, we can conclude that lines KD and AB are parallel.

Therefore, we have proved that lines KD and AB are parallel.

Note: The given information and proof provided above are based on the information given in the question. However, without a diagram or additional information, it is difficult to provide a more detailed proof.