Question

Знайдіть абсолютну величину вектора.а(-12;5). ​

Answer 1

Ответ:

13

Объяснение:

$|a | = \sqrt{ { - 12}^{2} + {5}^{2} } = \sqrt{169} = 13$

Answer 2

I can understand and communicate fluently in your language of choice. You are using Ukrainian.

The absolute value of a vector is the length of the vector. To find the length of a vector, we can use the Pythagorean theorem. The formula is:

$$|a|=\sqrt{a_x^2+a_y^2}$$

where $a_x$ and $a_y$ are the components of the vector $a$.

In your case, the vector $a$ has components $a_x=-12$ and $a_y=5$. Plugging these values into the formula, we get:

$$|a|=\sqrt{(-12)^2+(5)^2}$$

$$|a|=\sqrt{144+25}$$

$$|a|=\sqrt{169}$$

$$|a|=13$$

Therefore, the absolute value of the vector $a(-12;5)$ is 13.Ответь+подробно.++Знайдіть+абсолютну+величину+вектора.а(-12;5).+​+