Question

Знайдіть кути трикутника якщо 2 з них відносяться як 4:11 а 3 кут дорівнює 75°​

Answer 1

Ответ:

28°,  77°,   75°​

Объяснение:

Нехай ∠1=4х°,  ∠2=11х°, тоді

4х+11х+75=180°;  15х=105;  х=7

∠1=4*7=28°,  ∠2=11*7=77°

Answer 2

Finding the Angles of a Triangle

To find the angles of a triangle, we need to use the information provided. Let's break down the given information:

- Two of the angles are in a ratio of 4:11. - One of the angles is 75°.

Let's denote the angles as A, B, and C, with A being the angle in the 4:11 ratio, B being the angle in the 4:11 ratio, and C being the angle of 75°.

To find the values of angles A and B, we can set up the following equation based on the given ratio:

A:B = 4:11

We can express this equation as:

A = (4/15) * (A + B)

Since the sum of the angles in a triangle is always 180°, we can also express the equation as:

A + B + C = 180°

Now, let's substitute the value of angle C, which is 75°, into the equation:

A + B + 75° = 180°

Simplifying the equation, we have:

A + B = 105°

Now, we can substitute the value of A + B from the equation above into the equation A = (4/15) * (A + B):

A = (4/15) * 105°

Simplifying further, we find:

A = 28°

Since A + B = 105°, we can find the value of B:

B = 105° - 28° = 77°

Therefore, the angles of the triangle are approximately:

A ≈ 28°, B ≈ 77°, C = 75°

Please note that these values are approximate, as the given information does not provide exact values for the angles.