Question

Найдите углы треугольника АВС, если угол А на 20° меньше угла В и в 2 раза меньше угла С.

Answer 1

Ответ:

Объяснение:

∠А - х°, ∠В - (х+20)°, ∠С=2х°;

х+(х+20)+2х=180

4х=160

х=160/4=40° - ∠А;

(40+20)=60° - ∠В;

40*2=80° - ∠С.

Answer 2

Finding the Angles of Triangle ABC

To find the angles of triangle ABC, we are given the following information: - Angle A is 20° less than angle B. - Angle A is half the measure of angle C.

Let's denote the measures of the angles as follows: - Angle A = x - Angle B = x + 20 - Angle C = 2x

To find the values of these angles, we can use the fact that the sum of the interior angles of a triangle is always 180°.

We can set up the following equation: x + (x + 20) + 2x = 180

Solving for x: 4x + 20 = 180 4x = 160 x = 40

Now that we have the value of x, we can find the measures of angles A, B, and C: - Angle A = 40° - Angle B = 40° + 20° = 60° - Angle C = 2 * 40° = 80°

Therefore, the angles of triangle ABC are: - Angle A = 40° - Angle B = 60° - Angle C = 80°