Question

С 1. Расставьте коэффициенты в уравнениях. Определите ко. (в моль) участвующих и образующихся веществ. Опред ций. 1)FeS + HCI - FeCI2 + H2S 2)Cu2O + O2 --CuO 3)HNO3-- NO2+O2+H2O -- 4)Al2O3 + H2SO4 - Al(SO4)3+ H2O Pb(NO3)2 + Kİ - PbI2 + KNO3 даю 30 баллов, срочнозаранее спасибо​

Answer 1

Объяснение:

1) Реакция обмена

FeS + 2HCI → FeCI2 + H2S

3моль → 2моль

2) реакция соединения

2Cu2O + O2 → 4CuO

3моль → 4моль

3) реакция разложения

4HNO3 → 4NO2 + O2 + 2H2O

4моль → 7моль

4)реакция обмена

Al2O3 + 3H2SO4 → Al2(SO4)3 + 3H2O

4моль → 4моль

5)реакция обмена

Pb(NO3)2 + 2Kİ → PbI2 + 2KNO3

3моль → 3моль

Answer 2

Balancing Chemical Equations and Determining Stoichiometric Coefficients

To balance the given chemical equations and determine the stoichiometric coefficients, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's go through each equation step by step:

1) FeS + HCl -> FeCl2 + H2S

To balance this equation, we start by counting the number of atoms for each element on both sides:

Fe: 1 on the left, 1 on the right S: 1 on the left, 1 on the right H: 1 on the left, 2 on the right Cl: 1 on the left, 2 on the right

To balance the hydrogen (H) and chlorine (Cl) atoms, we need to add a coefficient of 2 in front of HCl:

FeS + 2HCl -> FeCl2 + H2S

Now, the equation is balanced.

2) Cu2O + O2 -> CuO

Let's count the number of atoms for each element:

Cu: 2 on the left, 1 on the right O: 3 on the left, 2 on the right

To balance the copper (Cu) atoms, we need to add a coefficient of 2 in front of CuO:

Cu2O + O2 -> 2CuO

Now, the equation is balanced.

3) HNO3 -> NO2 + O2 + H2O

Counting the number of atoms for each element:

H: 1 on the left, 2 on the right N: 1 on the left, 1 on the right O: 3 on the left, 4 on the right

To balance the hydrogen (H) atoms, we need to add a coefficient of 2 in front of H2O:

HNO3 -> NO2 + O2 + 2H2O

Now, the equation is balanced.

4) Al2O3 + H2SO4 -> Al(SO4)3 + H2O

Counting the number of atoms for each element:

Al: 2 on the left, 1 on the right O: 3 on the left, 4 on the right H: 2 on the left, 2 on the right S: 1 on the left, 3 on the right

To balance the aluminum (Al) atoms, we need to add a coefficient of 2 in front of Al(SO4)3:

2Al2O3 + 3H2SO4 -> Al(SO4)3 + 3H2O

Now, the equation is balanced.

5) Pb(NO3)2 + KI -> PbI2 + KNO3

Counting the number of atoms for each element:

Pb: 1 on the left, 1 on the right N: 2 on the left, 1 on the right O: 6 on the left, 3 on the right K: 1 on the left, 1 on the right I: 2 on the left, 2 on the right

The equation is already balanced.

To determine the coefficients in moles of the substances involved and formed in the reactions, we need to know the initial amounts of the reactants. Without that information, we cannot provide specific values for the coefficients in moles.

I hope this helps! Let me know if you have any further questions.