Question

В реакцию с соляной кислотой(HCl) вступило 5,4г алюминия(Al). Вычислите число моль и объем, образующегося водорода(H2) и рассчитайте, сколько моль соляной кислоты(HCl) вступило в реакцию 2Al + 6HCl → 2AlCl3 + 3H2 1. Сalculate the actual amount of aluminum substance Вычислите фактическое количество вещества алюминия_______________моль ПОМОГИТЕ ПОЖАЛУЙСТА

Answer 1

Дано:

m(Al)=5,4г

M(Al)=27 г/моль

Vм=22,4 л/моль

Решение:

2Al+6HCl--->2AlCl3+3H2

n(Al)=m(Al):M

n(Al)=5,4:27=0,2моль

n(HCl)=3n(Al)=0,6моль

n(H2)=n(HCl):2=0,3моль

V=Vм*n

V(H2)=22,4*0,3=6,72л

Answer 2

Calculation of the Number of Moles and Volume of Hydrogen Gas Produced

To calculate the number of moles and volume of hydrogen gas (H2) produced when 5.4g of aluminum (Al) reacts with hydrochloric acid (HCl), we can use the balanced chemical equation for the reaction:

2Al + 6HCl → 2AlCl3 + 3H2

First, let's calculate the number of moles of aluminum (Al) using its molar mass. The molar mass of aluminum is 26.98 g/mol.

The number of moles of aluminum (Al) can be calculated using the formula:

Number of moles = Mass / Molar mass

Substituting the values, we get:

Number of moles of aluminum (Al) = 5.4g / 26.98 g/mol

Now, let's calculate the number of moles of hydrochloric acid (HCl) that reacted. According to the balanced chemical equation, the stoichiometric ratio between aluminum (Al) and hydrochloric acid (HCl) is 2:6. This means that for every 2 moles of aluminum, 6 moles of hydrochloric acid react.

Using the number of moles of aluminum (Al) calculated above, we can determine the number of moles of hydrochloric acid (HCl) that reacted:

Number of moles of hydrochloric acid (HCl) = (Number of moles of aluminum (Al) * 6) / 2

Next, let's calculate the number of moles of hydrogen gas (H2) produced. According to the balanced chemical equation, the stoichiometric ratio between aluminum (Al) and hydrogen gas (H2) is 2:3. This means that for every 2 moles of aluminum, 3 moles of hydrogen gas are produced.

Using the number of moles of aluminum (Al) calculated above, we can determine the number of moles of hydrogen gas (H2) produced:

Number of moles of hydrogen gas (H2) = (Number of moles of aluminum (Al) * 3) / 2

Finally, let's calculate the volume of hydrogen gas (H2) produced. We can use the ideal gas law, which states that the volume of a gas is directly proportional to the number of moles and temperature, and inversely proportional to pressure.

Since the temperature and pressure are not provided in the question, we cannot calculate the exact volume of hydrogen gas. However, we can use the molar volume of an ideal gas at standard temperature and pressure (STP) as an approximation. The molar volume of an ideal gas at STP is 22.4 L/mol.

The volume of hydrogen gas (H2) produced can be calculated using the formula:

Volume = Number of moles * Molar volume

Substituting the values, we get:

Volume of hydrogen gas (H2) = Number of moles of hydrogen gas (H2) * Molar volume

Please note that the actual volume of hydrogen gas produced may vary depending on the temperature and pressure conditions of the reaction.

Calculation of the Actual Amount of Aluminum Substance

To calculate the actual amount of aluminum substance, we need to convert the mass of aluminum (Al) to moles. We can use the molar mass of aluminum (Al), which is 26.98 g/mol.

The actual amount of aluminum substance can be calculated using the formula:

Amount of substance = Mass / Molar mass

Substituting the values, we get:

Amount of substance of aluminum (Al) = 5.4g / 26.98 g/mol

Therefore, the actual amount of aluminum substance is ___________ moles.

Please note that the actual amount of aluminum substance may vary depending on the accuracy of the given mass and the molar mass of aluminum.

I hope this helps! Let me know if you have any further questions.