Question

РЕШИТЕ ЗАДАЧУ КАКУЮ МАССУ СОДЫ НУЖНО ДОБАВИТЬ 300 МИЛИЛИТРОВ ЧТОБЫ ПОЛУЧИТЬ 5% РАСТВОРА ПОМОГИТЕ ПОЖАЛУЙСТА ​

Answer 1

Ответ:

15,8

Объяснение:

300мл воды равен 300гр воды т.к. плотность воды равен 1г/мл

300--- 95%

15,78=х--5%

15,78~ 15,8

проверяем:

С% = 15,8 *100% / (15,8+300) = 5%

Answer 2

Calculating the Mass of Soda Required to Make a 5% Solution

To calculate the mass of soda needed to make a 5% solution with 300 milliliters, we can use the formula:

% concentration = (mass of solute / volume of solution) * 100

We can rearrange this formula to solve for the mass of the solute:

mass of solute = (% concentration * volume of solution) / 100

Calculation

Using the given information: - % concentration = 5% - volume of solution = 300 milliliters

We can calculate the mass of soda required:

mass of solute = (5 * 300) / 100

mass of solute = 15 grams

Therefore, 15 grams of soda need to be added to 300 milliliters to obtain a 5% solution.

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