Question

Известно, что ордината некоторой точки прямой, являющейся графиком уравнения 12x-5y=132, равна 0. Найдите абсциссу этой точки. Ребят помогите пожалуйста , очень нужно

Answer 1

Finding the Abscissa of a Point on a Line

To find the abscissa of a point on a line, we need to solve the given equation for the x-coordinate when the y-coordinate is 0.

The equation given is: 12x - 5y = 132.

To find the abscissa, we set y = 0 and solve for x.

Substituting y = 0 into the equation, we get:

12x - 5(0) = 132.

Simplifying the equation, we have:

12x = 132.

To solve for x, we divide both sides of the equation by 12:

x = 132 / 12.

Evaluating the expression, we find:

x = 11.

Therefore, the abscissa of the point on the line with the equation 12x - 5y = 132, where the ordinate is 0, is x = 11.

I hope this helps! Let me know if you have any further questions.