Question

Мне нужно №4 a) и b) и №5, кому не сложно, прошу. С подробным решением.

Answer 1

$\frac{y^{ \frac{1}{2}}+7 }{y+7y^{ \frac{1}{2}}} = \frac{y^{ \frac{1}{2}}+7}{y^{ \frac{1}{2}}(y^{ \frac{1}{2}}+7)} = \frac{1}{y^{ \frac{1}{2}}} = \frac{1}{ \sqrt{y} }$

$\frac{b-9}{b^{ \frac{1}{2}} +3} = \frac{(b^{ \frac{1}{2}} -3)*(b^{ \frac{1}{2}} +3)}{b^{ \frac{1}{2}} +3} =b^{ \frac{1}{2}} -3= \sqrt{b} -3$

$(\frac{c^{0,5}}{c^{0,5}-d^{0,5}} - \frac{d}{c-c^{0,5}d^{0,5}} )* \frac{5c^{1,5}}{c^{0,5}+d^{0,5}} =\\=(\frac{c^{0,5}}{c^{0,5}-d^{0,5}} - \frac{d}{c^{0,5}(c^{0,5}-d^{0,5})} )* \frac{5c^{1,5}}{c^{0,5}+d^{0,5}} =\\=\frac{c-d}{c^{0,5}(c^{0,5}-d^{0,5})} * \frac{5c^{1,5}}{c^{0,5}+d^{0,5}} =\\=\frac{(c^{0,5}-d^{0,5})*(c^{0,5}+d^{0,5})}{c^{0,5}(c^{0,5}-d^{0,5})} * \frac{5c^{1,5}}{c^{0,5}+d^{0,5}} =\frac{5c^{1,5}}{c^{0,5}} =5c$