Question

Найдите область определения функции

Answer 1

$y=\frac{\sqrt{x-3}}{\sqrt{16-x^2}}\\\\OOF:\; \; \left \{ {{x-3\geq 0} \atop {16-x^2>0}} \right. \; \; \left \{ {{x\geq 3} \atop {(4-x)(4+x)>0}} \right. \; \left \{ {{x\geq 3} \atop {x\in (-4,4)}} \right. \; \Rightarrow \; \; \boxed {x\in [\, 3,4)}\\\\znaki\; (4-x)(4+x):\; \; \; ---(-4)+++(4)---$