Question

решить неравенство 4cos8x+√8=0

Answer 1

4 cos8x=-√8

cos8x=-√8\4

cos8x=-√(8\16)

cos8x=-√(1\2)

cos8x=-√2\2

8x=+-П-П\4+2Пk

x=+-П\8-П\32+Пk\4

Ответ: +-П\8-П\32+Пk\4

Answer 2

4cos8x + V8=0

4cos8x = -2V2

cos8x=-V2/2

8x=+-3p/4 + 2pk

x=+-3p/32 + pk/4