Question

2x-4 / x³-8 Решите Тема сокращение алгебрических дробей!!!

Answer 1

$\frac {2x-4}{x^3-8}=\frac {2(x-2)}{(x-2)(x^2+2x+4)}=\frac {2}{x^2+2x+4}$

Answer 2

2x-4 / x³-8=2(х-2)/(x-2)(x²+2x+4)=2/x²+2x+4

Answer 3

Simplifying Algebraic Fractions

To simplify the algebraic fraction 2x - 4 / x³ - 8, we can factorize the numerator and denominator and cancel out common factors.

Let's start by factoring the numerator and denominator:

Numerator: 2x - 4 - We can factor out a common factor of 2: 2(x - 2).

Denominator: x³ - 8 - This is a difference of cubes, which can be factored as (x - 2)(x² + 2x + 4).

Now, we can rewrite the fraction with the factored forms:

(2(x - 2)) / ((x - 2)(x² + 2x + 4))

Next, we can cancel out the common factor of (x - 2):

2 / (x² + 2x + 4)

Therefore, the simplified form of the algebraic fraction 2x - 4 / x³ - 8 is 2 / (x² + 2x + 4).

Please let me know if you need any further assistance!