Question

((log2(корень из 5 - 1) + log2(корень из 5 + 1)) log3 49 //log3 7

Answer 1

Вот решение твоего примера

Answer 2

I can help you solve this logarithmic expression. Here are the steps:

- First, we need to simplify the expression inside the parentheses using the property of logarithms that says log_b (x*y) = log_b (x) + log_b (y). We get:

((log2(корень из 5 - 1) + log2(корень из 5 + 1)) + log3 49) // log3 7

= (log2((корень из 5 - 1) * (корень из 5 + 1)) + log3 49) // log3 7

- Next, we can use the difference of squares formula to simplify the product of (корень из 5 - 1) and (корень из 5 + 1). We get:

= (log2(5 - 1) + log3 49) // log3 7

= (log2 4 + log3 49) // log3 7

- Then, we can use the property of logarithms that says log_b (b^x) = x to simplify the logarithms of powers. We get:

= (2 + 2) // 1

= 4 // 1

= 4

- Therefore, the final answer is 4.

I hope this helps you understand how to solve logarithmic expressions. If you need more help, you can use some online tools such as [Symbolab](https://www.symbolab.com/solver/logarithms-calculator) or [Microsoft Math Solver](https://mathsolver.microsoft.com/en/solve-problem/%60log%201%20.%20%60log%202%20.%20%60log%203%20.%20%60log%204%20%3D) to check your answers and see more examples. You can also watch some videos on [Khan Academy](https://www.khanacademy.org/math/algebra-home/alg-exp-and-log/alg-logarithmic-equations/v/solving-logarithmic-equations) or to learn more about the properties of logarithms and how to use them.