Question

Решите графическую систему 2у=-4 х+8 ; 4у=-12х

Answer 1

{2y=-4x+8|:2
{4y=-12x|:4
{y=-2x+4
{y=-3x
теперь строишь графики этих функций и находишь их точки пересечения

Answer 2

Problem Statement

We are given the following system of equations: - Equation 1: 2u = -4x + 8 - Equation 2: 4u = -12x

We need to solve this system of equations.

Solution

To solve this system of equations, we can use the method of substitution or elimination. Let's use the method of substitution.

From Equation 2, we can express u in terms of x: - Equation 2: 4u = -12x - Dividing both sides by 4: u = -3x

Now, substitute the value of u in Equation 1 with -3x: - Equation 1: 2u = -4x + 8 - Substitute u with -3x: 2(-3x) = -4x + 8 - Simplify: -6x = -4x + 8 - Add 4x to both sides: -2x = 8 - Divide both sides by -2: x = -4

Now that we have the value of x, we can substitute it back into Equation 2 to find the value of u: - Equation 2: 4u = -12x - Substitute x with -4: 4u = -12(-4) - Simplify: 4u = 48 - Divide both sides by 4: u = 12

Therefore, the solution to the system of equations is x = -4 and u = 12.

Note: The solution to the system of equations is x = -4 and u = 12.