Question

Скорость автобуса в 3 раза меньше,чем скорость легковой машины. Они выехали из двух городов навстречу друг другу одновременно.Расстояние между городами 560 км.Найдите скорость автобуса,если встретились машины через 4 часа.

Answer 1

пусть скорость атобуса х, тогда скорость легковой машины 3х. В пути они были по 4 часа. Значит, автобус прошел до встречи 4х км, машина 12х км. Уравнение

4х+12x=560, 16x=560, x=35, т.е. скорость автобуса равна 35 км/ч

Answer 2

Problem Analysis

We are given that the speed of the bus is 3 times less than the speed of the car. The distance between the two cities is 560 km, and the cars started from their respective cities simultaneously. We need to find the speed of the bus if the cars met after 4 hours.

Solution

Let's assume the speed of the car is x km/h. According to the problem, the speed of the bus is 3 times less than the speed of the car, so the speed of the bus is x/3 km/h.

We can use the formula speed = distance / time to find the distance traveled by each vehicle.

The car traveled for 4 hours, so the distance traveled by the car is x * 4 km.

The bus also traveled for 4 hours, so the distance traveled by the bus is (x/3) * 4 km.

Since the total distance between the cities is 560 km, we can set up the equation:

(x * 4) + ((x/3) * 4) = 560

Simplifying the equation:

(4x) + (4x/3) = 560

Multiplying through by 3 to eliminate the fraction:

12x + 4x = 1680

16x = 1680

Dividing both sides by 16:

x = 105

Therefore, the speed of the car is 105 km/h.

The speed of the bus is 3 times less than the speed of the car, so the speed of the bus is 105/3 = 35 km/h.

Answer

The speed of the bus is 35 km/h.