Question

корень((1-корень(3))в квадрате) с решением пожалуйста

Answer 1

$(1-\sqrt{3})^{2}=\sqrt{1^{2}-2\sqrt{3}+(\sqrt{3})^{2}} \\\\1+3-2\sqrt{3}\\\\4-2\sqrt{3}=2(2-\sqrt{3})$

Answer 2

(1-√3)²=1²-2√3+(√3)²=1+3-2√3=4-2√3=2(2-√3)

Answer 3

Calculation of the expression

To calculate the expression (1 - √3)^2, we can follow these steps:

1. Start by simplifying the expression inside the parentheses: 1 - √3. 2. Square the simplified expression: (1 - √3)^2.

Let's calculate it step by step:

1. Simplifying the expression inside the parentheses: - 1 - √3

2. Squaring the simplified expression: - (1 - √3)^2

To simplify the expression, we can use the formula (a - b)^2 = a^2 - 2ab + b^2.

In this case, a = 1 and b = √3.

Substituting the values into the formula, we get:

1^2 - 2 * 1 * √3 + (√3)^2

Simplifying further:

1 - 2√3 + 3

Combining like terms:

4 - 2√3

Therefore, the simplified expression is 4 - 2√3.

Let me know if you have any further questions!