Question

Найдите такую точку графика линейной функции у=4/3х+8,абсцисса которой равна ординате

Answer 1

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Answer 2

Finding the Point on the Graph

To find the point on the graph of the linear function y = (4/3)x + 8 where the abscissa (x-coordinate) is equal to the ordinate (y-coordinate), we can set the equation equal to itself and solve for x.

Let's set x = y and substitute it into the equation:

(4/3)x + 8 = x

To solve for x, we can subtract x from both sides of the equation:

(4/3)x - x + 8 = 0

Combining like terms, we have:

(1/3)x + 8 = 0

To isolate x, we can subtract 8 from both sides of the equation:

(1/3)x = -8

Finally, we can multiply both sides of the equation by 3 to get rid of the fraction:

x = -24

Therefore, the abscissa of the point on the graph of the linear function where the abscissa is equal to the ordinate is x = -24.

Please note that the above solution is based on the given equation and the assumption that the abscissa and ordinate are equal.