Question

Сократить дробь х-у/3у-3х; х кубе -4хкву/28у-7х; а в4степ - 6акуб/36-акв; nкв-16n+64/128-2nкв?

Answer 1

Ответ будет таким ...............

Answer 2

Simplifying Fractions:

To simplify the given fractions, we need to find the greatest common divisor (GCD) of the numerator and denominator and divide both by it. Let's simplify each fraction step by step:

1. Simplifying (х - у) / (3у - 3х): - Factor out -1 from the numerator: -(у - х) / (3у - 3х) - Factor out 3 from the denominator: -(у - х) / 3(у - х) - Cancel out the common factor (у - х): -1/3

Therefore, the simplified form of (х - у) / (3у - 3х) is -1/3.

2. Simplifying (х^3 - 4х^2у) / (28у - 7х): - Factor out х from the numerator: х(х^2 - 4ху) / (28у - 7х) - Factor out 7 from the denominator: х(х^2 - 4ху) / 7(4у - х) - Cancel out the common factor х: (х^2 - 4ху) / 7(4у - х)

Therefore, the simplified form of (х^3 - 4х^2у) / (28у - 7х) is (х^2 - 4ху) / 7(4у - х).

3. Simplifying а^(4степ) - 6а^куб / (36 - а^2кв): - Factor out а^2 from the numerator: а^2(а^2 - 6а) / (36 - а^2кв) - Factor out а^2 from the denominator: а^2(а^2 - 6а) / (36 - а^2кв) - Cancel out the common factor (а^2 - 6а): а^2 / (36 - а^2кв)

Therefore, the simplified form of а^(4степ) - 6а^куб / (36 - а^2кв) is а^2 / (36 - а^2кв).

4. Simplifying n^2 - 16n + 64 / (128 - 2n^2): - Factor the numerator: (n - 8)^2 / (128 - 2n^2) - Factor out 2 from the denominator: (n - 8)^2 / 2(64 - n^2) - Cancel out the common factor (64 - n^2): (n - 8)^2 / 2(8 + n)(8 - n)

Therefore, the simplified form of n^2 - 16n + 64 / (128 - 2n^2) is (n - 8)^2 / 2(8 + n)(8 - n).

Please let me know if you need further assistance!