Question

Сколько имеется натуральных чисел, делящихся без остатка на 9 и удовлетворяющих условию 203 <= x <=250? Решите пожалуйста с решением.

Answer 1

Исходное уравнение 203 <= x <=250
за х берем p*9 cследовательно
203<p*9<250
Получается : 203/9 и 250/9
Выходит: 22.6< p < 27.7 
cледует 
23<28
Ответ: имеется 5 натуральных чисел от 23 до 28

Answer 2

203≤x≤250
Число делится без остатка на 9, если сумма цифр делится на 9. Ближайшее число будет 216 и потом прибавляя 9 получишь остальные т.е.:216;225;234;243.

Answer 3

Calculation of Natural Numbers Divisible by 9 between 203 and 250

To find the number of natural numbers that are divisible by 9 and satisfy the condition 203 ≤ x ≤ 250, we can use the following steps:

1. Determine the smallest multiple of 9 that is greater than or equal to 203. In this case, the smallest multiple of 9 greater than or equal to 203 is 207.

2. Determine the largest multiple of 9 that is less than or equal to 250. In this case, the largest multiple of 9 less than or equal to 250 is 243.

3. Calculate the number of multiples of 9 between 207 and 243 (inclusive). To do this, subtract the smallest multiple from the largest multiple and divide the result by 9. Then add 1 to account for the inclusive range.

Number of multiples of 9 = (243 - 207) / 9 + 1 = 36 / 9 + 1 = 4 + 1 = 5.

Therefore, there are 5 natural numbers between 203 and 250 that are divisible by 9 and satisfy the given condition.

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