Question

Корень из 2x-3 = x-3 пожалуйста помогите

Answer 1

√(2x - 3) = x - 3
2x - 3 ≥ 0
x - 3 ≥ 0
2x - 3 = (x - 3)^2

x≥1.5
x≥3
2x - 3 = x^2 - 6x + 9

x≥3
x^2 - 8x + 12 = 0, D = 64 - 4*12 = 64 - 48 = 16
x1 = (8 - 4)/2 = 4/2 = 2 < 3 - посторонний корень
x2 = (8+4)/2 = 12/2 = 6

Ответ: 6

Answer 2

Решение на листке , думаю так решается

Answer 3

Problem Statement

You are looking for the solution to the equation √(2x-3) = x-3. Let's solve it step by step.

Solution

To solve the equation √(2x-3) = x-3, we can start by squaring both sides of the equation to eliminate the square root:

(√(2x-3))^2 = (x-3)^2

Simplifying the equation, we get:

2x-3 = (x-3)^2

Expanding the square on the right side of the equation, we have:

2x-3 = x^2 - 6x + 9

Rearranging the equation to bring all terms to one side, we get:

x^2 - 8x + 12 = 0

Now, we have a quadratic equation. We can solve it by factoring, completing the square, or using the quadratic formula. Let's factor the equation:

(x-2)(x-6) = 0

Setting each factor equal to zero, we have:

x-2 = 0 or x-6 = 0

Solving for x in each equation, we get:

x = 2 or x = 6

Therefore, the solutions to the equation √(2x-3) = x-3 are x = 2 and x = 6.

Answer

The solutions to the equation √(2x-3) = x-3 are x = 2 and x = 6.