Question

Петр приобрел 8 билетов лотереи "Надежда" и 6 билетов лотереи "Удача".Билет лотереи "Удача" стоил a р.,а лотереи "Надежда" на 10 % дороже.Найдите стоимость покупки.

Answer 1

6a+8(a+a*0.1) -> 6a+8a+0.8a=14,8a - стоимость покупки 8 билетов надежда и 6 билетов удача

Answer 2

Calculation of the Purchase Cost

To find the cost of the purchase, we need to determine the price of a ticket for each lottery and then calculate the total cost.

Let's assume the price of a ticket for the "Удача" lottery is a rubles. According to the given information, the price of a ticket for the "Надежда" lottery is 10% more expensive than the "Удача" lottery.

Therefore, the price of a ticket for the "Надежда" lottery is a + 0.1a = 1.1a rubles.

Now, let's calculate the total cost of the purchase.

- Number of tickets for the "Надежда" lottery: 8 - Number of tickets for the "Удача" lottery: 6

The total cost can be calculated as follows:

Total cost = (Number of tickets for "Надежда" lottery * Price of a ticket for "Надежда" lottery) + (Number of tickets for "Удача" lottery * Price of a ticket for "Удача" lottery)

Total cost = (8 * 1.1a) + (6 * a)

Simplifying the expression:

Total cost = 8.8a + 6a

Total cost = 14.8a

Therefore, the cost of the purchase is 14.8a rubles.

Please note that the exact value of a is not provided in the question, so we cannot determine the specific cost of the purchase without this information.