Question

решите систему:x^2+2y=6y=x-18 класс

Answer 1

Х^2+2у=6

У=х-1

Х^2+2х-2=6

Х^+2х-8=0

По т виета х1=-4 х2=2

У1=-5
 у2=1

Answer 2

System of Equations

The given system of equations is:

1. Equation 1: x^2 + 2y = 6 2. Equation 2: y = x - 18

To solve this system of equations, we can substitute Equation 2 into Equation 1 and solve for x.

Solving the System of Equations

Substituting Equation 2 into Equation 1, we get:

x^2 + 2(x - 18) = 6

Expanding and simplifying the equation, we have:

x^2 + 2x - 36 = 6

Rearranging the equation, we get:

x^2 + 2x - 42 = 0

Now, we can solve this quadratic equation for x.