Question

Опытная швея справится с выполнением заказа за 1 час , а её ученица за 3 часа . Сколько времени будет выполнять заказ швея вместе с ученицей при совместной работе ? Ответ выразите в часах .

Answer 1

1) за 1 час опытная швея делает весь заказ 2) за 1час ученица делает 1/3 заказа 3) за 1 час опытная швея и ее ученица делают суммарно 1+1/3=4/3 заказа 4) 1:4/3=3/4 часа - нужно при совместной работе швее и ученице чтоб выполнить один заказ ответ: 0.75 часа

Answer 2

Calculation of Time Taken by the Seamstress and Her Apprentice

To calculate the time it will take for the seamstress and her apprentice to complete the order together, we need to consider their individual completion times.

According to the information provided, the experienced seamstress can complete the order in 1 hour, while her apprentice takes 3 hours to complete the same order.

To determine the time it will take for them to complete the order together, we can use the concept of work rates. The work rate is the amount of work done per unit of time.

Let's assume that the work rate of the experienced seamstress is 1 unit of work per hour. This means that she can complete the entire order in 1 hour.

Similarly, the work rate of the apprentice is 1/3 units of work per hour. This means that the apprentice can complete 1/3 of the order in 1 hour.

When they work together, their work rates are additive. So the combined work rate of the seamstress and her apprentice is 1 + 1/3 = 4/3 units of work per hour.

To find the time it will take for them to complete the order together, we can use the formula:

Time = Total Work / Combined Work Rate

Since the total work is 1 (representing the entire order), we can substitute it into the formula:

Time = 1 / (4/3) = 3/4 hours

Therefore, it will take the seamstress and her apprentice 3/4 hours to complete the order together.

Please note that the calculation assumes a linear relationship between time and work rate, and it may not account for factors such as coordination and efficiency in a real-world scenario.