Question

Три фирмы получили от завода-производителя 236 компьютеров.Вторая фирма получила на 10% больше компьютеров,чем первая,а третья на 100 компьютеров меньше,чем первые две вместе.сколько компьютеров получила каждая фирма?

Answer 1

1-я фирма получила Х

2-я фирма получила Х+0,1Х (на 10%больше)

3-я фирма получила (Х+(Х+0,1Х))-100  - на 100 меньше, чем сумма 1-й и 2-й фирмы.

Уравнение: Х+Х+0,1Х+(Х+(Х+0,1Х))-100=236

Х=80. 

1-я фирма - 80

2-я фирма - 80+80*0,1=88

3-я фирма - 80+88-100=68

Answer 2

пусть х компьютеров получила первая фирма, тогда х+0,1х=1,1х комп-в получила вторая фирма и х+х+0,1х-100=2,1х-100 комп-в получила третья фирма. зная, что всего получили 236 комп-в, составляем уравнение х+1,1х+2,1х-100=236 4,2х=336

 

Answer 3

Problem Analysis

We are given that three companies received a total of 236 computers from a factory. The second company received 10% more computers than the first company, and the third company received 100 computers fewer than the sum of the first two companies. We need to determine how many computers each company received.

Solution

Let's assume that the first company received x computers.

According to the problem, the second company received 10% more computers than the first company. Therefore, the second company received x + 0.1x = 1.1x computers.

The third company received 100 computers fewer than the sum of the first two companies. So, the third company received (x + 1.1x) - 100 = 2.1x - 100 computers.

The total number of computers received by all three companies is given as 236. Therefore, we can write the equation:

x + 1.1x + (2.1x - 100) = 236

Simplifying the equation:

4.2x - 100 = 236

Adding 100 to both sides:

4.2x = 336

Dividing both sides by 4.2:

x = 80

So, the first company received 80 computers.

The second company received 10% more than the first company, which is 1.1 times the number of computers received by the first company:

1.1 * 80 = 88

Therefore, the second company received 88 computers.

The third company received 100 computers fewer than the sum of the first two companies:

(80 + 88) - 100 = 68

Therefore, the third company received 68 computers.

Answer

The first company received 80 computers, the second company received 88 computers, and the third company received 68 computers.