Question

Помогиье срочно.Из двух городов ,расстояние между ними которыми 500 км,вышли одновременно навстречу друг другу два поещда .Через 3 часа расстояние между нимт было 50 км.Найдите скорость каждогл,если скорость одного из них на 10 км/ч больще другогоа

Answer 1

Х-скорость одного ,х+10-скорость второго. Сказано что оба были в пути 3ч
3х+3(х+10)- скорость сближения
3х+3(х+10)=500-50
3х+3х+30=450
6х=450-30
6х=420
Х=70 скорость одного
70+10=80 скорость другого

Answer 2

Problem Analysis

We have two trains traveling towards each other from two cities, and after 3 hours, the distance between them is 50 km. We need to find the speed of each train, given that the speed of one train is 10 km/h greater than the other.

Solution

Let's assume the speed of the slower train is x km/h. Then the speed of the faster train will be x + 10 km/h.

We can use the formula distance = speed × time to calculate the distance traveled by each train.

After 3 hours, the slower train will have traveled a distance of 3x km, and the faster train will have traveled a distance of 3(x + 10) km.

According to the problem, the total distance between the two trains is 500 km, and after 3 hours, the distance between them is 50 km. Therefore, we can set up the following equation:

3x + 3(x + 10) = 500 - 50

Simplifying the equation:

6x + 30 = 450

6x = 420

x = 70

So, the speed of the slower train is 70 km/h, and the speed of the faster train is 70 + 10 = 80 km/h.

Answer

The speed of the slower train is 70 km/h, and the speed of the faster train is 80 km/h.