Question

рыболов в 5 часов утра на моторной лодке отправился от пристани против течения реки, через некоторое время бросил якорь, 2 часа ловил рыбу и вернулся обратно в 10 часов утра того же дня. На какое расстояние от пристани он отплыл, если скорость реки равна 2 км/ч, а собственная скорость лодки 6 км/ч?

Answer 1

1) 10-5=5(ч)- он всего рыбачил

2) 5-2=3(ч) - до того, как он бросил якорь

3) 6-2=4(км/ч) - V лодки против течения

4) 4х3=12(км)- на это S уплыл рыбак от пристани

Ответ: 12 км.

Answer 2

This is a mathematical problem that can be solved by using the formula of relative speed and time. Here is a detailed solution:

- Let x be the time (in hours) that the fisherman spent sailing against the current before he dropped the anchor. - Let y be the time (in hours) that he spent sailing with the current on his way back to the pier. - Let d be the distance (in kilometers) that he sailed away from the pier. - The total time that he spent on the boat is 10 - 5 = 5 hours, of which 2 hours he spent fishing. Therefore, the time that he spent sailing is 5 - 2 = 3 hours. This means that x + y = 3. - The speed of the boat relative to the water is 6 km/h, and the speed of the current is 2 km/h. Therefore, the speed of the boat against the current is 6 - 2 = 4 km/h, and the speed of the boat with the current is 6 + 2 = 8 km/h. - The distance that he sailed is equal to the product of the speed and the time. Therefore, d = 4x = 8y. This implies that x = 2y. - Substituting x = 2y into x + y = 3, we get 2y + y = 3, which gives y = 1. This means that x = 2. - Therefore, the fisherman spent 2 hours sailing against the current and 1 hour sailing with the current. The distance that he sailed away from the pier is d = 4x = 4 * 2 = 8 km.

The answer is 8 km. You can find similar problems and solutions on the web .