Question

В одном пакете было в 5 раз больше конфет чем во втором.когда с первого пакета положили 16 конфет во второй пакет конфет стало поровну.сколько конфет было в начале в пакетах?????

Answer 1

Х конфет - во  ІІ пакете
5х конфет - в І пакете
5х-16=х+16
5х-х=16+16
4х=32
х=32:4
х=8(конф) - было во ІІ пакете
8*5=40(конф) - было в І пакете

Answer 2

Solution:

Let's denote the number of candies in the first package as x and the number of candies in the second package as y.

Given: - The first package had 5 times more candies than the second package: x = 5y. - When 16 candies were taken from the first package and put into the second package, they became equal: (x-16) = (y+16).

We can solve these two equations to find the initial number of candies in each package.

Calculations:

Using the first equation x = 5y, we can substitute the value of x in the second equation:

(5y - 16) = (y + 16)

Solving for y: 5y - 16 = y + 16 4y = 32 y = 8

Substituting the value of y back into the first equation to find x: x = 5 * 8 x = 40

Answer:

So, there were 40 candies in the first package and 8 candies in the second package initially.