Question

ПОМОГИТЕ,ПОЖАЛУЙСТАА!!!Из городов A и В навстречу друг другу одновременно выехали мотоциклист и велосипедист. Мотоциклист приехал в В на56 минут раньше ,чем велосипедист приехал в А ,а встретились они через 21 минут после выезда сколько часов затратил на путь из В в А велосипедист?

Answer 1

1 - расстояние
x мин - время велосипедиста
(x-56) мин - время мотоциклиста
(1/x + 1/(x-56))*21=1, общий знаменатель х(х-56)
21х-1176+21х=х²-56х
x²-98x+1176=0
D=9604-4704=4900
x=(98+70)/2=(84 мин)=1час 24мин -  затратил на путь из В в А велосипедист

Answer 2

Problem Analysis

We are given that a motorcyclist and a cyclist start simultaneously from cities A and B, respectively. The motorcyclist arrives in city B 56 minutes before the cyclist arrives in city A. They meet each other 21 minutes after their departure. We need to determine how many hours the cyclist spent traveling from city B to city A.

Solution

Let's assume that the cyclist traveled for x hours from city B to city A. Since the motorcyclist arrived in city B 56 minutes before the cyclist arrived in city A, we can say that the motorcyclist traveled for x + 56/60 hours.

We are also given that they met each other 21 minutes after their departure. This means that the motorcyclist traveled for x + 56/60 - 21/60 hours.

Since the distance traveled by both the motorcyclist and the cyclist is the same, we can set up the following equation:

Distance = Speed × Time

Let's assume the speed of the motorcyclist is v1 and the speed of the cyclist is v2. The distance traveled by the motorcyclist is v1 × (x + 56/60 - 21/60), and the distance traveled by the cyclist is v2 × x.

Since the distances are equal, we can set up the equation:

v1 × (x + 56/60 - 21/60) = v2 × x

Now we can solve this equation to find the value of x, which represents the number of hours the cyclist spent traveling from city B to city A.

Let's calculate the value of x using the given information and the equation above.