Question

Задача: мне запомнился аттракцион «заяц в колесе». сколько времени длился этот номер цирковой программы, если диаметр колеса 2м, скорость зайца 6 м/с и колесо сделало 150 оборотов.

Answer 1

D=2 м  n=150  v=6 м/с   t-?
Длина окружности колеса l=πd.
Путь, который пробежал заяц - s=πdl  ⇒
Время аттракциона t=s/v=πdl/v=3.14*2*150/6≈157 (c).
Ответ: аттракцион длился 157 с (2 мин 37 с).

Answer 2

Calculation of the Duration of the Circus Act

To calculate the duration of the circus act "Zayats v Kolese" (Rabbit in the Wheel), we need to consider the diameter of the wheel, the speed of the rabbit, and the number of wheel rotations.

Given: - Diameter of the wheel: 2 meters - Speed of the rabbit: 6 m/s - Number of wheel rotations: 150

To calculate the duration, we can use the formula:

Duration = Distance / Speed

The distance traveled by the rabbit can be calculated using the formula:

Distance = Circumference of the wheel * Number of wheel rotations

The circumference of the wheel can be calculated using the formula:

Circumference = π * Diameter

Substituting the given values into the formulas, we can calculate the duration of the circus act.

Calculation Steps:

1. Calculate the circumference of the wheel: - Circumference = π * Diameter - Circumference = 3.14 * 2 - Circumference = 6.28 meters

2. Calculate the distance traveled by the rabbit: - Distance = Circumference * Number of wheel rotations - Distance = 6.28 * 150 - Distance = 942 meters

3. Calculate the duration of the circus act: - Duration = Distance / Speed - Duration = 942 / 6 - Duration = 157 seconds

Therefore, the circus act "Zayats v Kolese" lasted approximately 157 seconds.

Please note that the above calculation assumes that the rabbit maintains a constant speed throughout the act and that there are no other factors affecting the duration.