Question

Из двух пунктов А и В, расстояние между которыми равно 10 км, одновременно в противоположных направлениях выехали велосипедист и легковой автомобиль. Через 24 мин расстояние между ними стало равным 40 км. Найдите скорость велосипедиста, если известно, что она в 4 раза меньше скорости автомобиля.

Answer 1

40-10=30км,

30/24=1,25км/мин  общая скорость  ,

4х+х=1,25,

5х=1,25,

х=1,25/5,

х=0,25км/мин=15км/ч скорость велосепедиста,

15*4=60 км/ч скорость автомобиля

Answer 2

Given Information

The distance between points A and B is 10 km. A cyclist and a car simultaneously set off from these points in opposite directions. After 24 minutes, the distance between them became 40 km. It is known that the cyclist's speed is 4 times less than the speed of the car.

Solution

Let's denote the speed of the car as V and the speed of the cyclist as v.

The total distance covered by both the car and the cyclist in 24 minutes is 40 km, so we can set up the equation: V * (24/60) + v * (24/60) = 40

We also know that the speed of the cyclist is 4 times less than the speed of the car: v = V / 4

Substituting the value of v in the first equation, we get: V * (24/60) + (V / 4) * (24/60) = 40

Solving for V: V = 32 km/h

So, the speed of the car is 32 km/h.

Now, substituting the value of V in the equation for the speed of the cyclist: v = 32 / 4 = 8 km/h

Therefore, the speed of the cyclist is 8 km/h.

Conclusion

The speed of the cyclist is 8 km/h.