Question

Помогите решить методом алгебраического сложения {х+3у=8 3х-3у=0 Реально очень срочно

Answer 1

Здесь все просто, ненужно домножать, сразу складываем первое со вторым:
игрики сокращаются и остается:
4х=8
значит х=2
подставляем х в любое из двух изноч. уравнений и находим у:
4+3у=8
у=4/3.

Answer 2

Держи)Вот все расписала, а дальше подставляем в первое уравнение значения х и получаем: 2+3у=8 3у=6 у=2))

Answer 3

Algebraic Addition Method to Solve Equations

To solve the system of equations using the algebraic addition method, we can follow these steps:

1. Identify the Equations: - The given equations are: - \(x + 3y = 8\) - \(3x - 3y = 0\)

2. Multiply Equations (if necessary): - In this case, we don't need to multiply any of the equations to make the coefficients of \(x\) or \(y\) equal.

3. Add or Subtract the Equations: - We can add the two equations to eliminate the variable \(y\). - \(x + 3y + 3x - 3y = 8 + 0\) - \(4x = 8\)

4. Solve for the Variable: - Now, we can solve for \(x\). - \(4x = 8\) - \(x = 2\)

5. Substitute and Solve for the Other Variable: - Once we have the value of \(x\), we can substitute it back into one of the original equations to solve for \(y\). - Using the first equation: \(2 + 3y = 8\) - \(3y = 6\) - \(y = 2\)

6. Check the Solution: - It's important to check the solution by substituting the values of \(x\) and \(y\) into both original equations to ensure they satisfy both equations.

Therefore, the solution to the system of equations is: - \(x = 2\) - \(y = 2\)

This method allows us to find the values of \(x\) and \(y\) that satisfy both equations simultaneously.