Question

А) Постройте график функции y=2x-3; б) Проходит ли график этой функции через точку А (-38;-73)

Answer 1

А) Графиком функции у=2х-3 является прямая проходящая через точки
х=0  у=-3
х=3  у=2·3-3=3

б) Подставим координаты точки А в уравнение прямой
у=-73  х=-38
-73=2·(-38)-3
-73=-76-3
-73=-79- неверно.
О т в е т. не проходит

Answer 2

Graph of the Function y = 2x - 3

To plot the graph of the function y = 2x - 3, we can use the given equation to find several points and then connect them to visualize the graph.

The table of values for the function y = 2x - 3 is as follows:

| x | y | | --- | --- | | -2 | -7 | | -1 | -5 | | 0 | -3 | | 1 | -1 | | 2 | 1 |

Now, let's plot these points on a graph to visualize the function.

Verification of the Point (-38, -73)

To check if the graph of the function y = 2x - 3 passes through the point A(-38, -73), we can substitute x = -38 into the equation y = 2x - 3 and verify if it satisfies the equation.

Substituting x = -38 into the equation y = 2x - 3: y = 2(-38) - 3 y = -76 - 3 y = -79

The calculated value for y when x = -38 is -79, not -73. Therefore, the point A(-38, -73) does not lie on the graph of the function y = 2x - 3.

Conclusion: The graph of the function y = 2x - 3 does not pass through the point A(-38, -73).

I hope this helps! If you have any further questions or need additional assistance, feel free to ask.