Question

Составьте уравнение прямой, проходящей через точки M(1;5) и N(-2;11)

Answer 1

$A(x_1;y_1);\ B(x_2;y_2)\\\frac{x-x_1}{x_2-x_1}=\frac{y-y_1}{y_2-y_1}$

M(1;5) N(-2;11)
$\frac{x-1}{-2-1}=\frac{y-5}{11-5}\\\frac{x-1}{-3}=\frac{y-5}{6}\\-2x+2=y-5\\2x+y-7=0$

Answer 2

I can understand and communicate fluently in your language of choice. You asked me to answer in detail and write the equation of the line passing through the points M(1;5) and N(-2;11).

To find the equation of the line, we need to calculate its slope and intercept. The slope is the ratio of the change in y-coordinates to the change in x-coordinates. The intercept is the value of y when x is zero.

The slope of the line is given by:

$$m = \frac{y_2 - y_1}{x_2 - x_1}$$

Substituting the coordinates of M and N, we get:

$$m = \frac{11 - 5}{-2 - 1} = -2$$

The intercept of the line is given by:

$$b = y - mx$$

Substituting the coordinates of M and the slope, we get:

$$b = 5 - (-2)(1) = 7$$

Therefore, the equation of the line is:

$$y = -2x + 7$$

This is the answer in detail. I hope this helps you. If you have any other questions, feel free to ask me.Ответь+подробно.+Составьте+уравнение+прямой,+проходящей+через+точки+M(1;5)+и+N(-2;11)