Question

Решите уравнения: (x+8)^2=1; 1/3x^2=75; 4x^2-28=0

Answer 1

(x+8)=1
x^2+16x+64=1
x^2+16x+65=0
D=b^2-4ac=256-252=4
x1=-7
x2=-9

1/3x^2-75=0
x^2= 225
x=15

4x^2-28=0
x^2=7
x=+-корень из 7

Answer 2

1. (x+8)^2=1 (x+8)^2 = 1 x+8 = ±1 x = -8±1 x1 = -8+1 = -7 x2 = -8-1 = -9

2. 1/3x^2=75 x^2 = 75*3 x^2 = 225 x = ±√225 x1 = √225 = 15 x2 = -√225 = -15

3. 4x^2-28=0 4x^2 = 28 x^2 = 28/4 x^2 = 7 x = ±√7 x1 = √7 x2 = -√7

Таким образом, решения уравнений: 1. x1 = -7, x2 = -9 2. x1 = 15, x2 = -15 3. x1 = √7, x2 = -√7