Question

Найдити сумму превых 10 челенов арефметической прогрессий

Answer 1

$S_{10}=\frac{a_1+a_{10}}{2}*10=5(a_1+a_{10})\\ili\\S_{10}=\frac{2a_1+(10-1)*d}{2}*10=5(2a_1+9d)$

Answer 2

Calculating the Sum of the First 10 Terms of an Arithmetic Progression

To find the sum of the first 10 terms of an arithmetic progression, we can use the formula:

S(n) = n/2 * (a(1) + a(n))

Where: - S(n) is the sum of the first n terms - n is the number of terms - a(1) is the first term - a(n) is the nth term

Using the given information, we can calculate the sum of the first 10 terms of the arithmetic progression.

Calculation

Using the provided formula and the given values: - a(1) = 2 - a(2) = 5 - d = a(2) - a(1) = 5 - 2 = 3 - n = 10

We can calculate the sum as follows:

S(10) = (10/2) * (2 + a(10)) = 5 * (2 + 44) = 5 * 46 = 230

Therefore, the sum of the first 10 terms of the arithmetic progression is 230.

[[2 #]]