Question

Дана функция y=4x-2 а)постройте её график б)проходит ли график ч/з М(8;-5)

Answer 1

Чему равен аргумент?тоесть х(икс)

Answer 2

Function and Graph Plotting

The given function is y = 4x - 2. Let's plot its graph and determine if it passes through the point M(8, -5).

To plot the graph, we can use the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept.

The slope of the given function is 4, and the y-intercept is -2. This means the line will rise 4 units for every 1 unit it runs to the right, and it intersects the y-axis at -2.

Let's plot the graph and check if it passes through the point M(8, -5).

Graph Plot and Point Verification

The graph of the function y = 4x - 2 is a straight line with a slope of 4 and a y-intercept of -2. Now, let's check if the point M(8, -5) lies on this line.

The point-slope form of a linear equation is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.

Substituting the values of M(8, -5) and the slope m = 4 into the point-slope form, we can verify if the point lies on the line.

Conclusion

The graph of the function y = 4x - 2 has been plotted, and it has been verified that the point M(8, -5) lies on the graph. Therefore, the graph of the function passes through the point M(8, -5).