Question

Помогите пожалуйста решить задачу по алгебре с оформление и решением Двое рабочих, работая вместе, завершили работу за 6 дней. Сколько дней потребовалось бы каждому рабочему на выполнение этой работы, если одному для это требуется на 5 дней меньше, чем другому? Пожалуйста если знаете напишите!!!!

Answer 1

Решение :
х дней первому 
х+5 дней второму 
примем всю работу за 1 
1/х д в час делает первый 
1/(х+5) дет в час делает второй 
1/6 дет в час делают вместе 
1/х +1/(х+5)=1/6 
х^2-7х-30=0 
х1=10 и х2=-3(не подходит) 
10дней требуется первому и 10+5=15 дней второму

Answer 2

Problem Statement

You have asked for help in solving an algebra problem. The problem states that two workers, working together, completed a job in 6 days. You want to find out how many days each worker would take to complete the job individually, given that one worker takes 5 days less than the other.

Solution

Let's denote the time taken by the first worker as x days and the time taken by the second worker as x - 5 days. The combined work rate of the two workers is 1 job per 6 days.

Work Rate Equation

The work rate equation can be expressed as: 1/x + 1/(x-5) = 1/6

Solving the Equation

To solve this equation, we can first find a common denominator and then simplify the equation. After simplifying, we can solve for x to find the time taken by the first worker, and then calculate the time taken by the second worker.

Conclusion

By solving the equation, we can find the number of days each worker would take to complete the job individually.

Let's proceed with solving the equation to find the solution.